The hardware and bandwidth for this mirror is donated by dogado GmbH, the Webhosting and Full Service-Cloud Provider. Check out our Wordpress Tutorial.
If you wish to report a bug, or if you are interested in having us mirror your free-software or open-source project, please feel free to contact us at mirror[@]dogado.de.
Chapter 10 – Analysing discrete data –
Exercise solutions and Code Boxes
David Warton
2022-08-24
Exercise 10.1: Crabs on seaweed
David and Alistair… observed the following presence
(+) / absence (-)} patterns for crabs (across
10 replicates):
| 5 |
0 |
- |
| 5 |
0 |
+ |
| 5 |
0 |
+ |
| 5 |
0 |
- |
| 5 |
0 |
- |
| 5 |
2 |
- |
| 5 |
2 |
- |
| 5 |
2 |
+ |
| 5 |
2 |
- |
| 5 |
2 |
- |
| … |
… |
… |
| 10 |
10 |
+ |
They would like to know if there is any evidence of a difference
in crab presence patterns with Distance of Isolation. How should they
analyse the data?
They are looking for evidence of a difference at different values of
Dist so will be wanting to do a hypothesis test. Because
they have presence-absence data they should be thinking of a generalised
linear model with binomial response, as in Code Box 10.1.
Exercise 10.2: Do offshore wind farms affect fish communities?
Lena and colleagues… [were] collecting paired data before and
after wind farm construction, at 36 stations in each of three zones
(Wind Farm, North, or
South):
| Wind Farm |
Before |
WF1 |
0 |
| Wind Farm |
After |
WF1 |
0 |
| South |
Before |
S1 |
5 |
| South |
After |
S1 |
0 |
| North |
Before |
N1 |
0 |
| North |
After |
N1 |
0 |
| Wind Farm |
Before |
WF2 |
1 |
| Wind Farm |
After |
WF2 |
1 |
| … |
… |
… |
… |
| North |
After |
N36 |
0 |
Lena wants to know if there is any evidence of a change in eel
abundance at wind farm stations, as compared to others, following
construction of the wind farm. How should she analyse the data?
She is looking for evidence of a difference across different values
of Zone when Impact=After so will be wanting
to do a hypothesis test. This is a BACI design, so she would be
particularly interested in the Zone:Impact interaction.
Because she has count data with plenty of zeros, this should be analysed
using a generalised linear model (assuming a negative binomial or
Poisson response, as in Code Box 10.1).
Exercise 10.3: Invertebrate response to bush regeneration}
Anthony wants to evaluate how well invertebrate communities are
re-establishing following bush regeneration efforts.
| C |
0 |
| R |
3 |
| R |
1 |
| R |
3 |
| C |
1 |
| R |
2 |
| R |
12 |
| R |
1 |
| R |
18 |
| R |
0 |
He wants to know if there is any evidence that bush regeneration
is working. How should he analyse the data?
He is looking for evidence of an effect of revegetation so will be
wanting to do a hypothesis test for a Treatment effect.
Because he has count data, with zeros, this should be analysed using a
generalised linear model (assuming a negative binomial or Poisson
response, as in Code Box 10.1).
Code Box 10.1: Example GLM fits for Exercises 10.1-3.}
For Exercise 10.1:
library(ecostats)
data(seaweed)
seaweed$CrabPres = seaweed$Crab>0
ft_crab = glm(CrabPres~Time*Dist, family=binomial("cloglog"),
data=seaweed)
For Exercise 10.2: \begin{verbatim}
data(windFarms)
eels = windFarms$abund[,16]
ft_eels = glm(eels~Station+Year*Zone,family="poisson",
data=windFarms$X)
#> Warning: glm.fit: fitted rates numerically 0 occurred
For Exercise 10.3:
data(reveg)
Haplotaxida=reveg$abund[,12]
library(mvabund)
worms = reveg$abund$Haplotaxida
ft_worms = manyglm(worms~treatment,family="negative.binomial", data=reveg)
Code for Fig. 10.5
data(reveg)
library(mvabund)
revegMV=mvabund(reveg$abund)
treatment=reveg$treatment
meanvar.plot(revegMV~treatment,legend=T,col=c("darkorange","darkgreen"),main="Poisson")
#> START SECTION 2
#> Plotting if overlay is TRUE
#> using grouping variable Poisson 7 mean values were 0 and could
#> not be included in the log-plot
#> using grouping variable Poisson 10 variance values were 0 and could not
#> be included in the log-plot
#> FINISHED SECTION 2
x=10^(seq(-1,3.8,length=100))
lines(x,x,type="l",col="red")
plot of chunk fig10.5
meanvar.plot(revegMV~treatment,legend=T,col=c("darkorange","darkgreen"), main="Negative binomial")
#> START SECTION 2
#> Plotting if overlay is TRUE
#> using grouping variable Negative binomial 7 mean values were 0 and could
#> not be included in the log-plot
#> using grouping variable Negative binomial 10 variance values were 0 and could not
#> be included in the log-plot
#> FINISHED SECTION 2
x=10^(seq(-1,3.8,length=100))
points(x,x+x^2,type="l",col="darkblue")
plot of chunk fig10.5
Code Box 10.2: A summary of a GLM fit to the crab presence-absence
data of Exercise 10.1
seaweed$Dist = as.factor(seaweed$Dist)
ft_crab = glm(CrabPres~Time*Dist, family=binomial("cloglog"),
data=seaweed)
summary(ft_crab)
#>
#> Call:
#> glm(formula = CrabPres ~ Time * Dist, family = binomial("cloglog"),
#> data = seaweed)
#>
#> Deviance Residuals:
#> Min 1Q Median 3Q Max
#> -1.3537 -0.6681 -0.6681 1.0108 2.1460
#>
#> Coefficients:
#> Estimate Std. Error z value Pr(>|z|)
#> (Intercept) -2.3282 1.5046 -1.547 0.122
#> Time 0.1656 0.1741 0.952 0.341
#> Dist2 -1.5921 2.5709 -0.619 0.536
#> Dist10 -0.5843 2.1097 -0.277 0.782
#> Time:Dist2 0.1683 0.2899 0.581 0.561
#> Time:Dist10 0.1169 0.2399 0.487 0.626
#>
#> (Dispersion parameter for binomial family taken to be 1)
#>
#> Null deviance: 71.097 on 56 degrees of freedom
#> Residual deviance: 62.999 on 51 degrees of freedom
#> AIC: 74.999
#>
#> Number of Fisher Scoring iterations: 5
Code Box 10.3: Dunn-Smyth residual plots for the crab data, using
the mvabund package
library(mvabund)
ftMany_crab = manyglm(CrabPres~Time*Dist,family=binomial("cloglog"),
data=seaweed)
plotenvelope(ftMany_crab, which=1)
plot of chunk box10.3
Exercise 10.4: Counts of Ostracods in habitat configuration
experiment.
What sort of model would you use for Ostracod counts?
with(seaweed,boxplot(Ost~Dist))
plot of chunk ex10.4
As this is a count variable with plenty of small counts (and zeros in
each category), I am thinking a GLM. To start with we could consider a
Poisson regression, if there were no overdispersion, or negative
binomial regression.
The terms to add to the model I guess are Time and
Dist, as orthogonal factors. As previously
Wmass might also be useful.
How would you check assumptions?
Look for a fan-shape on a residual plot to check the mean-variance
assumption, as in Code Box 10.4.
Code Box 10.4: Assumption checking for Ostracod counts of Exercise
10.4.}
seaweed$logWmass = log(seaweed$Wmass)
ft_countOst=manyglm(Ost~logWmass+Time*Dist,data=seaweed,
family="poisson")
par(mfrow=c(1,3),mar=c(3,3,1.5,0.5),mgp=c(1.75,0.75,0))
plotenvelope(ft_countOst, which=1:3, n.sim=99) # for a scale-location plot as well
(Note that plotenvelope was
run with just 99 iterations, to speed up computation
time.)
library(MASS) #this line is currently needed to deal with a bug but prob redundant soon
par(mfrow=c(1,3),mar=c(3,3,1.5,0.5),mgp=c(1.75,0.75,0))
ft.countOstNB=manyglm(Ost~logWmass+Time*Dist,data=seaweed)
plotenvelope(ft.countOstNB, which=1:3, n.sim=99)
plot of chunk box10.4b
Exercise 10.5: Checking the Poisson assumption on the wind farm
data.
Refit the model using the manyglm function, and
hence construct a residual plot
data(windFarms)
eels = windFarms$abund[,16]
ft_eels = manyglm(eels~Station+Year*Zone,family="poisson",
data=windFarms$X)
par(mfrow=c(1,3),mar=c(3,3,1.5,0.5),mgp=c(1.75,0.75,0))
plotenvelope(ft_eels, which=1:3, n.sim=99)
#> Error in glm.fit(x = structure(c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, :
#> NA/NaN/Inf in 'x'
#> Error in glm.fit(x = structure(c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, :
#> NA/NaN/Inf in 'x'
plot of chunk ex10.5
Does the Poisson assumption look reasonable?
There is no evidence of a fan shape, residuals are close to a
straight line on the normal quantile plot, so it looks pretty good to
me.
Exercise 10.6: Checking the Poisson assumption for the worm
counts.}
Refit the model using the manyglm function under the
Poisson assumption, and hence construct a residual plot.
data(reveg)
Haplotaxida=reveg$abund[,12]
worms = reveg$abund$Haplotaxida
ft_worms = manyglm(worms~treatment,family=poisson(), data=reveg)
par(mfrow=c(1,2),mar=c(3,3,1.5,0.5),mgp=c(1.75,0.75,0))
plotenvelope(ft_worms, which=1:2, n.sim=99)
plot of chunk box10.6Poisson
Also fit a negative binomial to the data and construct a residual
plot.
ft_wormsNB = manyglm(worms~treatment,family="negative.binomial", data=reveg)
par(mfrow=c(1,2),mar=c(3,3,1.5,0.5),mgp=c(1.75,0.75,0))
plotenvelope(ft_wormsNB, which=1:2, n.sim=99)
plot of chunk box10.6NB
Can you see any differences between plots?
The Poisson model fans out more and has a couple of residuals that
are unusually large (see normal quantile plot). It also may have a trend
line on the residual vs fits plots that slips outside its simulation
envelope.
Compare BIC for the two models, using the BIC
function.
BIC(ft_worms, ft_wormsNB)
#> df BIC
#> ft_worms 2 80.55508
#> ft_wormsNB 3 53.93523
Which model has the better fit to the worm counts?
Well BIC suggests the negative binomial model is way better,
corroborating the result from the normal quantile plots.
Code Box 10.5: R code using the anova
function to test the key hypotheses of interest to David and Alistair in
Exercise 10.1.
anova(ft_crab, test="Chisq")
#> Analysis of Deviance Table
#>
#> Model: binomial, link: cloglog
#>
#> Response: CrabPres
#>
#> Terms added sequentially (first to last)
#>
#>
#> Df Deviance Resid. Df Resid. Dev Pr(>Chi)
#> NULL 56 71.097
#> Time 1 6.6701 55 64.427 0.009804 **
#> Dist 2 1.0265 53 63.400 0.598553
#> Time:Dist 2 0.4012 51 62.999 0.818257
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Any evidence of an effect of Isolation distance on
crabs?
Nope :(
Note the Time effect is significant here but not in
Code Box 10.2. Why do you think that might be?
Code Box 10.2 uses a Wald test, which is known to give wacky answers
for separable models, see Maths Box 10.6 for details.
Exercise 10.7: Testing if there a wind farm effect
What model should be fitted, to handle the pairing
structure?
We can fit a glm as previously but need to include
Station as one of the predictors, to handle
station-to-station variation in eel abundance:
ft_eelsSt = glm(eels~Station+Year+Year:Zone,family="poisson",
data=windFarms$X)
#> Warning: glm.fit: fitted rates numerically 0 occurred
It would be OK to write Year*Zone but the
Zone main effect is redundant because of the
Station main effect. You could also use a mixed model with
a random intercept for Station.
Fit the appropriate model and test for an effect of wind
farm.
anova(ft_eelsSt,test='Chisq')
#> Analysis of Deviance Table
#>
#> Model: poisson, link: log
#>
#> Response: eels
#>
#> Terms added sequentially (first to last)
#>
#>
#> Df Deviance Resid. Df Resid. Dev Pr(>Chi)
#> NULL 178 246.714
#> Station 107 169.443 71 77.270 0.0001145 ***
#> Year 1 1.906 70 75.365 0.1674431
#> Year:Zone 2 4.821 68 70.544 0.0897813 .
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
There is marginal evidence of a Year-Zone interaction.
Code Box 10.6: Model-based inference for Anthony’s worm counts from
Exercise 10.3.
ftmany_Hap=manyglm(Haplotaxida~treatment,family="negative.binomial",
data=reveg)
anova(ftmany_Hap)
#> Time elapsed: 0 hr 0 min 0 sec
#> Analysis of Deviance Table
#>
#> Model: Haplotaxida ~ treatment
#>
#> Multivariate test:
#> Res.Df Df.diff Dev Pr(>Dev)
#> (Intercept) 9
#> treatment 8 1 2.811 0.158
#> Arguments: P-value calculated using 999 iterations via PIT-trap resampling.
Code Box 10.7: Design-based inference for David’s and Alistair’s
crab data using mvabund.
ftMany_crab = manyglm(CrabPres~Time*Dist, family=binomial("cloglog"),
data=seaweed)
anova(ftMany_crab)
#> Time elapsed: 0 hr 0 min 1 sec
#> Analysis of Deviance Table
#>
#> Model: CrabPres ~ Time * Dist
#>
#> Multivariate test:
#> Res.Df Df.diff Dev Pr(>Dev)
#> (Intercept) 56
#> Time 55 1 6.670 0.014 *
#> Dist 53 2 1.026 0.654
#> Time:Dist 51 2 0.401 0.873
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
#> Arguments: P-value calculated using 999 iterations via PIT-trap resampling.
Any important differences from results David and Alistair
previously obtained in Code Box 10.5?
Nope, looks very similar actually! I guess the Time
effect is slightly less significant now but the conclusion doesn’t
really change, there is still reasonable evidence of a Time
effect.
Code Box 10.8: Getting the wrong answer by ignoring overdispersion
in Anthony’s worm counts from Exercise 10.3.
ft_wormPois = glm(Haplotaxida~treatment, family="poisson", data=reveg)
anova(ft_wormPois,test="Chisq")
#> Analysis of Deviance Table
#>
#> Model: poisson, link: log
#>
#> Response: Haplotaxida
#>
#> Terms added sequentially (first to last)
#>
#>
#> Df Deviance Resid. Df Resid. Dev Pr(>Chi)
#> NULL 9 63.946
#> treatment 1 11.668 8 52.278 0.0006359 ***
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
ft_wormmanyPois = manyglm(Haplotaxida~treatment,family="poisson",
data=reveg)
anova(ft_wormmanyPois)
#> Time elapsed: 0 hr 0 min 0 sec
#> Analysis of Deviance Table
#>
#> Model: Haplotaxida ~ treatment
#>
#> Multivariate test:
#> Res.Df Df.diff Dev Pr(>Dev)
#> (Intercept) 9
#> treatment 8 1 11.67 0.204
#> Arguments: P-value calculated using 999 iterations via PIT-trap resampling.
Code Box 10.9: Using an observation-level random effect for a
binomial response
data(seedsTemp)
seedsTemp$propGerm = seedsTemp$NumGerm / seedsTemp$NumSown
plot(propGerm/(1-propGerm)~Test.Temp,data=seedsTemp,log="y")
#> Warning in xy.coords(x, y, xlabel, ylabel, log): 5 y values <= 0 omitted from logarithmic plot
plot of chunk box10.9Load
library(lme4)
seedsTemp$ID = 1:length(seedsTemp$NumGerm)
ft_temp = glmer(cbind(NumGerm,NumSown-NumGerm)~poly(Test.Temp,2)+
(1|ID),data=seedsTemp,family="binomial")
summary(ft_temp)
#> Generalized linear mixed model fit by maximum likelihood (Laplace Approximation) ['glmerMod']
#> Family: binomial ( logit )
#> Formula: cbind(NumGerm, NumSown - NumGerm) ~ poly(Test.Temp, 2) + (1 | ID)
#> Data: seedsTemp
#>
#> AIC BIC logLik deviance df.resid
#> 212.7 218.1 -102.3 204.7 25
#>
#> Scaled residuals:
#> Min 1Q Median 3Q Max
#> -1.10831 -0.00896 0.06063 0.13519 0.33025
#>
#> Random effects:
#> Groups Name Variance Std.Dev.
#> ID (Intercept) 2.961 1.721
#> Number of obs: 29, groups: ID, 29
#>
#> Fixed effects:
#> Estimate Std. Error z value Pr(>|z|)
#> (Intercept) -0.5896 0.3428 -1.720 0.0854 .
#> poly(Test.Temp, 2)1 2.8770 1.9395 1.483 0.1380
#> poly(Test.Temp, 2)2 -3.6910 1.9227 -1.920 0.0549 .
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
#>
#> Correlation of Fixed Effects:
#> (Intr) p(T.T,2)1
#> ply(T.T,2)1 -0.060
#> ply(T.T,2)2 0.066 -0.147
Exercise 10.8: Anthony’s ant data.
Which model do you think is more appropriate for this dataset – a
Poisson or negative binomial?
This is a hard question to answer without fitting a model.
ants = reveg$abund$Formicidae
ants_Poisson = glm(ants~treatment,data=reveg,family=poisson())
par(mfrow=c(1,3),mar=c(3,3,1.5,0.5),mgp=c(1.75,0.75,0))
plotenvelope(ants_Poisson, which=1:3, n.sim=99)
plot of chunk ex10.8P
OK so a Poisson fit is spectacularly bad. Neither
smoother stays in its envelope, and the data on the normal quantile plot
do not stay anywhere near their envelope.
Plot the data – does there seem to be evidence of a treatment
effect?
with(reveg,boxplot(abund$Formicidae~treatment))
plot of chunk ex10.8plot
Not really! The ant counts in the control sites are similar to the
middle of those from the revegetated sites.
Use the glm function to fit a Poisson log-linear
model, and use this to test for a treatment effect. Did you get what you
expected?
anova(ants_Poisson,test='Chisq')
#> Analysis of Deviance Table
#>
#> Model: poisson, link: log
#>
#> Response: ants
#>
#> Terms added sequentially (first to last)
#>
#>
#> Df Deviance Resid. Df Resid. Dev Pr(>Chi)
#> NULL 9 985.74
#> treatment 1 62.345 8 923.39 2.882e-15 ***
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Whoah we are being told there is strongly significant evidence of a
treatment effect, a claim that should be treated with suspicion (no such
evidence on the boxplot above!)
Now use negative binomial regression to test for a treatment
effect.
ants = reveg$abund$Formicidae
ants_NB = manyglm(ants~treatment,data=reveg,family="negative.binomial")
anova(ants_NB)
#> Time elapsed: 0 hr 0 min 0 sec
#> Analysis of Deviance Table
#>
#> Model: ants ~ treatment
#>
#> Multivariate test:
#> Res.Df Df.diff Dev Pr(>Dev)
#> (Intercept) 9
#> treatment 8 1 0.765 0.542
#> Arguments: P-value calculated using 999 iterations via PIT-trap resampling.
Notice you have got a very different answer.
Yeah, like completely the opposite!!!
Which answer is more likely to be correct in this case?
par(mfrow=c(1,3),mar=c(3,3,1.5,0.5),mgp=c(1.75,0.75,0))
plotenvelope(ants_NB,which=1:3, n.sim=99)
plot of chunk ex10.8NBplots
Whereas the diagnostic plots for the Poisson model showed serious
problems, we have no such issues here. So the negative binomial
regression is a much better fit to the data. It produced (much!) larger
\(P\)-values because there is a lot of
overdispersion in the data, which a Poisson model is unable to account
for.
(Note that the simulation envelopes cover a broad range! This is
because of the small sample size. When comparing these plots to those
for the Poisson fit, notice that the y-axis scale on the negative
binomial plot is much smaller – the envelopes actually have similar
width in both sets of plots, they look different mostly because the axes
have different scales.)
Exercise 10.9: Worm counts with different numbers of pitfall
traps
How can we account for the different sampling effort at different
sites in our model?
Use an offset for log(pitfalls) as in Code Box 10.9.
Code Box 10.10: Adding an offset to the model for worm counts.
ftmany_hapoffset = manyglm(Haplotaxida~treatment+offset(log(pitfalls)),
family="negative.binomial", data=reveg)
anova(ftmany_hapoffset)
#> Time elapsed: 0 hr 0 min 0 sec
#> Analysis of Deviance Table
#>
#> Model: Haplotaxida ~ treatment + offset(log(pitfalls))
#>
#> Multivariate test:
#> Res.Df Df.diff Dev Pr(>Dev)
#> (Intercept) 9
#> treatment 8 1 2.889 0.143
#> Arguments: P-value calculated using 999 iterations via PIT-trap resampling.
Exercise 10.10: Anthony’s cockroaches
How should he analyse the data?
This looks like Exercise 10.9 and so could be analysed a similar way,
assuming assumptions are all satisfied. The main difference here is that
we have many zeros in the dataset (70%)…
roaches = reveg$abund$Blattodea
ftMany_roaches = manyglm(roaches~treatment,offset=log(pitfalls), family="poisson", data=reveg)
par(mfrow=c(1,3),mar=c(3,3,1.5,0.5),mgp=c(1.75,0.75,0))
plotenvelope(ftMany_roaches, which=1:3, n.sim=99)
plot of chunk ex10.10
anova(ftMany_roaches)
#> Time elapsed: 0 hr 0 min 0 sec
#> Analysis of Deviance Table
#>
#> Model: roaches ~ treatment
#>
#> Multivariate test:
#> Res.Df Df.diff Dev Pr(>Dev)
#> (Intercept) 9
#> treatment 8 1 16.68 0.006 **
#> ---
#> Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
#> Arguments: P-value calculated using 999 iterations via PIT-trap resampling.
Although we have many zeros in the dataset, they are all in the
treatment group, meaning that our observed predictor explains these
well. A Poisson model seems to fit the reasonably data well, and we can
conclude that there is very strong evidence of an effect of revegetation
on cockroaches (they disappeared from revegetated plots).
These binaries (installable software) and packages are in development.
They may not be fully stable and should be used with caution. We make no claims about them.
Health stats visible at Monitor.
